How wide is a widescreen monitor!?

Hey

I've been trying to work out how wide and how tall the picture will be on a
19inch widescreen monitor (16:9) that I just brought.

My maths has failed me. *embarrassed*. So can someone please demonstrate
nicely how to work it out.

Thankyou

Dan

16.6" x 9.3".

--
"War is the continuation of politics by other means.
It can therefore be said that politics is war without
bloodshed while war is politics with bloodshed."

"Dan" wrote in message
. uk...
Hey

I've been trying to work out how wide and how tall the picture will be on
a 19inch widescreen monitor (16:9) that I just brought.

My maths has failed me. *embarrassed*. So can someone please demonstrate
nicely how to work it out.

Thankyou

Dan

Cheers. Seems I'm gaining more width than I am losing height which is good.
Could you show the method you used to work that out please?

Danke

Dan

On Fri, 11 Aug 2006 01:42:36 +0100, "Dan"
wrote:

Cheers. Seems I'm gaining more width than I am losing height which is good.
Could you show the method you used to work that out please?

Danke

Dan




(hypotenuse)^2= (sideA)^2+ (sideB)^2 of a right-triangle...... (1)
(Pythagoras' theorem)

hypotenuese == diagonal screen measurement == the stated screen size.

and sideA/sideB = width/height = 16/9........................(2)
( for a true wide-screen display )

Then just do the math.

Using 19 inches diagonal and simplifying for sideA

19^2= (sideA) ^2 + (9/16*sideA)^2... substituting eq (2) in eq (1)

Collecting together the coefficients of (sideA)^2 and squaring the
9/16 term gives:-

19^2= [1+ 81/256] * (sideA)^2

361=337/256 * (sideA)^2

therefo

361*256/337 = (sideA)^2

Hence, sideA = Square Root of ( 361* 256/337 )

Using your calculator this gives

sideA= 16.559935..... inches

and side B= 9/16 * side A = 9.31496355..... inches

QED.

John Lewis

Pythagorean: sqrt(16^2+9^2) = 18.36
Ratio of w:h:diag is thus: 16:9:18.36

So if the diagonal is 19":
width = (16/18.36)x19 = 16.6"
height = (9/18.36)x19 = 9.3"
area = 16.6*9.3 = 154 in^2

A 4:3 19" monitor has 173 in^2 of screen area, so you are losing about 13%
desktop real estate. Better step up to a 21" or 24" if you want widescreen.
:-)

--
"War is the continuation of politics by other means.
It can therefore be said that politics is war without
bloodshed while war is politics with bloodshed."

"Dan" wrote in message
...
Cheers. Seems I'm gaining more width than I am losing height which is
good. Could you show the method you used to work that out please?

Danke

Dan

"First of One" wrote in message
...
Pythagorean: sqrt(16^2+9^2) = 18.36
Ratio of w:h:diag is thus: 16:9:18.36

So if the diagonal is 19":
width = (16/18.36)x19 = 16.6"
height = (9/18.36)x19 = 9.3"
area = 16.6*9.3 = 154 in^2

A 4:3 19" monitor has 173 in^2 of screen area, so you are losing about 13%
desktop real estate. Better step up to a 21" or 24" if you want
widescreen. :-)


Cheers mate.

Dan

"First of One" wrote in message
...
Pythagorean: sqrt(16^2+9^2) = 18.36
Ratio of w:h:diag is thus: 16:9:18.36

So if the diagonal is 19":
width = (16/18.36)x19 = 16.6"
height = (9/18.36)x19 = 9.3"
area = 16.6*9.3 = 154 in^2

A 4:3 19" monitor has 173 in^2 of screen area, so you are losing about 13%
desktop real estate. Better step up to a 21" or 24" if you want
widescreen. :-)

I've just done the maths (think its right) and with a 19inch crt the viewing
area is just under 18 inch but with 19inch widescreem lcd its 19inch I
think. So I think I'm slightly gaining some viewing space?

I got 162inch2 for widescreen and 155inch2 for crt.

Dan

sorry got 154inch2 for widescreen and 155inch2 for 4:3. Losing an inch. I
can live with that!

Cheers

Dan

Not only should your target purchase be compared against your existing CRT,
it should also be compared against alternatives on the market. My numbers
are for a 4:3 19" LCD monitor, which I believe are priced equal or lower
than widescreen monitors of the same size.

--
"War is the continuation of politics by other means.
It can therefore be said that politics is war without
bloodshed while war is politics with bloodshed."

"Dan" wrote in message
...
I've just done the maths (think its right) and with a 19inch crt the
viewing area is just under 18 inch but with 19inch widescreem lcd its
19inch I think. So I think I'm slightly gaining some viewing space?

I got 162inch2 for widescreen and 155inch2 for crt.

Dan

Most PC widescreen monitors are 16:10, so that's something to bear in mind
when making your calculations. 16:9 material will be shown with borders.

"First of One" wrote in message
...
Pythagorean: sqrt(16^2+9^2) = 18.36
Ratio of w:h:diag is thus: 16:9:18.36

So if the diagonal is 19":
width = (16/18.36)x19 = 16.6"
height = (9/18.36)x19 = 9.3"
area = 16.6*9.3 = 154 in^2

A 4:3 19" monitor has 173 in^2 of screen area, so you are losing about 13%
desktop real estate. Better step up to a 21" or 24" if you want
widescreen. :-)

--
"War is the continuation of politics by other means.
It can therefore be said that politics is war without
bloodshed while war is politics with bloodshed."

"Dan" wrote in message
...
Cheers. Seems I'm gaining more width than I am losing height which is
good. Could you show the method you used to work that out please?

Danke

Dan