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CBFalconer wrote:
Ben Pope wrote: General Schvantzkoph wrote: Power is V^2/R so reducing the core voltage reduces the power dramatically. I think that heat production in a chip is more about capacitance than resistance. The voltage and capacitance (and switching time) will affect the amount of current that flows, and that will determine the heat production. In CMOS logic the action consists of charging and discharging many small capacitances at the clock rate. The charge q transferred is proportional to V and C, i.e. dQ = CV. The time interval dT is inversely proportional to frequence, so the effective current I is dQ/dT, and the effective power is V*I. Since q is proportional to V, that gives the usual power vs V squared relationship, but power is also directly proportional to frequency. Just keep your eye on the fundamental ball, power is voltage times current. I good point well made. Much better than I tried to make it. :-p Ben -- A7N8X FAQ: www.ben.pope.name/a7n8x_faq.html Questions by email will likely be ignored, please use the newsgroups. I'm not just a number. To many, I'm known as a String... |
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It shold not overheat like this in that case, it has adequate (but barely)
airflow with its two intake fans in front http://www.modthebox.com/review287_4.shtml did you remove any plastic protection and put on thermal paste? maybe you can set a fan at top to get air out, but dont use the fine black grid - it will reduce the airflow by 75%. "Miss Perspicacia Tick" wrote in message ... I have an FX-53 based system on an SK8V board in a CoolerMaster Wave Master case. The HSF is a Swiftech MCX64-V with a Delta fan and the PSU is a 480W Tagan. The rest of the spec is as follows: - 1GB RAM 3xSATA HDs (2xRaptor in a RAID 0 array plus a WDC) 9800XT 256MB Audigy 2 Platinum Pro XS Plextor 708A Samsung combi I have a *serious* issue with overheating - and I do mean *SERIOUS*. With the side panel on, it *IDLES* at between 60-65°C (140-149°F) and once, when I was doing nothing more than designing a brochure in Publisher, it hit 70°C (167°F) and locked up. I have moved all obstructions from around the HSF and made sure everything is dust free (it's only a day old!) Is there a fault somewhere? I was lead to believe that the motherboard had smart temperature control - well 60-65 at idle tells me either it doesn't or it isn't working. Is there a setting I've overlooked in the BIOS (I didn't build it)? I don't have much spare cash to spend on any more cooling (and there isn't any room in the case for any more fans anyway!) I'm running it with the side off at the moment and it's stabilised at 45°C (113°F) - but I don't want to have to do that forever! I'm hoping for an idle temperature (with the side on) of around 35-45°C (95-113°F) and 50-55°C (122-131°F) under load. Achievable? I don't think it's asking *too* much, do you?! I've RTFM and it's not exactly explicit! How do I achieve what I consider to be the optimum running temperature?! I will call the bloke who built it on Monday, but I thought I'd ask here first - I know that MBM isn't known for its accuracy but, on this occasion, it's spot on (I've checked it with the BIOS). Can someone offer me some cooling solutions that won't empty my bank account?! Thanks |
#53
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General Schvantzkoph wrote:
On Mon, 21 Jun 2004 20:54:31 +0100, wrote: "Ben Pope" wrote in message ... General Schvantzkoph wrote: Power is V^2/R so reducing the core voltage reduces the power dramatically. I think that heat production in a chip is more about capacitance than resistance. The voltage and capacitance (and switching time) will affect the amount of current that flows, and that will determine the heat production. Ben Capacitive Reactance (Xc) If you had a pure Capacitive circut then the P = V^2/(Xc) might be correct Of course, it's a ton more complicated than this in a processor.. and I would have to wonder just how much total capacitance there is in a processor (I wouldnt guess it's a lot given it's size) ;P The leakage current is the resistive part, the capactance is reactive. The capactive part dominated in earlier generations but as line widths have become smaller the leakage has become much more significant. In both cases the power is related to the square of the core voltage. The reactive part is linearly related to the frequency, so reducing the clock frequency reduces the reactive power. If you lower the clock frequency and lower the core voltage you get a very large reduction in power. I wish I'd paid more attention in Physics! |
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