amdx wrote:

To prevent spambots I need to answer this question to confirm
registration to a forum.

If USB 3.1 Type-C Gen 2 speed is 10Gbps, What is the speed of 10Gbps in
MB/s (Answer must include MB/s):

I thought it would just be Gig to Meg or 1000, but I get that is an
invalid answer, So I googled and found:
" 10 Gigabit Ethernet speed 10 Gbit/s = 1250 Megabytes per second"
But that also gives me a that is an invalid answer.
Yes, I putting it in MB/s form, either 1000MB/s or 1250MB/s

Any ideas?
Mikek

Gbps = Giga*bit* per second (smallcase "b" means "bit")
MB/s = Mega*byte* per second (uppercase "B" means "byte")

You should already be aware there are 8 bits to a byte. Divide by 8 to
change bits to bytes. Then multiply by 1000 to change giga to mega
(which assumes they are talking gigabytes and megabytes based on a power
of 10 instead of gibibits and mebibytes based on a power of 2).

10 Gbps / (8 bits/byte) ) * 1000 = 1250 MB/s.

The question does not address the encoding overhead for each packet, as
Paul mentioned. "speed" may refer to the effective transfer rate
regardless of the packet overhead: what got delivered irregardless of
how it got packaged during transport. Data transfer rate will be less
than the "speed" of a protocol due to packaging overhead; however, most
users consider data transfer rate (for just the data blocks within the
packets) and the speed of the connection as the same.

Is this forum populated by Mensa members? A typical mathematical
CAPTCHA just asks for simple arithmetic computation, not for calculating
a Fourier transform or the primes within a variable range. Is it a
forum populated by USB engineers that are expected to intimately know
this stuff?